If it's not what You are looking for type in the equation solver your own equation and let us solve it.
a^2-2=-2
We move all terms to the left:
a^2-2-(-2)=0
We add all the numbers together, and all the variables
a^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{2}=0$
| u(2+u)–2u=16 | | 34-5y=y+16 | | 5(1+y)=3+2y | | 7x-41=x×8 | | 256=113z | | -4a-5=15 | | 7x-41=80-5x | | 10*120/x-2=80 | | 5=-2i+5 | | 10=9-t | | -2=3+m | | 4y+25=100 | | 0.40m+100=0.90m+50 | | 2x(3x+4)-1(3x+4)=0 | | 7.x-6=2.x+4 | | 3(x+2)+2(x+1)=3(x-1)+x | | 0=-d/4+4 | | -3m-12=-8+7m | | 2x+17=89 | | 7=j/2+2 | | 42=-7/6v | | 35=u/3+16 | | 46=5u-9 | | 7/8=y+6 | | 15y+18=-6y+24 | | 2(3x-2)=8x-4-2x | | 9-5u=46 | | m–=2+m2 | | z2=10 | | 5x(3x+20)5x(3x+20)=360 | | 16/24=x/9x | | (-2(x+1)+3x)-4=5 |